2x(x-3)+(2x-5)(x-4)/(x-4)(x-3)=25/3

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Solution for 2x(x-3)+(2x-5)(x-4)/(x-4)(x-3)=25/3 equation: 



2x(x-3)+(2x-5)(x-4)/(x-4)(x-3)=25/3

We move all terms to the left:

2x(x-3)+(2x-5)(x-4)/(x-4)(x-3)-(25/3)=0



Domain of the equation: (x-4)(x-3)!=0

We move all terms containing x to the left, all other terms to the right

x-4)(x!=3

x∈R



We add all the numbers together, and all the variables

2x(x-3)+(2x-5)(x-4)/(x-4)(x-3)-(+25/3)=0

We multiply parentheses

2x^2-6x+(2x-5)(x-4)/(x-4)(x-3)-(+25/3)=0

We get rid of parentheses

2x^2-6x+(2x-5)(x-4)/(x-4)(x-3)-25/3=0

We multiply parentheses ..

2x^2+(+2x^2-8x-5x+20)/(x-4)(x-3)-6x-25/3=0

We calculate fractions


2x^2+(-25x^2+175x-300)/(3x^2-21x+36)-6x+(6x^2-39x+60)/(3x^2-21x+36)=0

We multiply all the terms by the denominator


(-25x^2+175x-300)+2x^2*(3x^2-21x+36)-6x*(3x^2-21x+36)+(6x^2-39x+60)=0

We multiply parentheses

(-25x^2+175x-300)+2x^2*(3x^2-21x+36)-18x^3+126x^2-216x+(6x^2-39x+60)=0

We get rid of parentheses

-25x^2+2x^2*(3x^2-21x+36)-18x^3+126x^2+6x^2+175x-216x-39x-300+60=0

We do not support expression: x^3

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