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2x(x-3)-(x+1)(x-2)+11=1
We move all terms to the left:
2x(x-3)-(x+1)(x-2)+11-(1)=0
We add all the numbers together, and all the variables
2x(x-3)-(x+1)(x-2)+10=0
We multiply parentheses
2x^2-6x-(x+1)(x-2)+10=0
We multiply parentheses ..
2x^2-(+x^2-2x+x-2)-6x+10=0
We get rid of parentheses
2x^2-x^2+2x-x-6x+2+10=0
We add all the numbers together, and all the variables
x^2-5x+12=0
a = 1; b = -5; c = +12;
Δ = b2-4ac
Δ = -52-4·1·12
Δ = -23
Delta is less than zero, so there is no solution for the equation
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