2x(x-3)=x(2x+4)-80

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Solution for 2x(x-3)=x(2x+4)-80 equation:


Simplifying
2x(x + -3) = x(2x + 4) + -80

Reorder the terms:
2x(-3 + x) = x(2x + 4) + -80
(-3 * 2x + x * 2x) = x(2x + 4) + -80
(-6x + 2x2) = x(2x + 4) + -80

Reorder the terms:
-6x + 2x2 = x(4 + 2x) + -80
-6x + 2x2 = (4 * x + 2x * x) + -80
-6x + 2x2 = (4x + 2x2) + -80

Reorder the terms:
-6x + 2x2 = -80 + 4x + 2x2

Add '-2x2' to each side of the equation.
-6x + 2x2 + -2x2 = -80 + 4x + 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
-6x + 0 = -80 + 4x + 2x2 + -2x2
-6x = -80 + 4x + 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
-6x = -80 + 4x + 0
-6x = -80 + 4x

Solving
-6x = -80 + 4x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4x' to each side of the equation.
-6x + -4x = -80 + 4x + -4x

Combine like terms: -6x + -4x = -10x
-10x = -80 + 4x + -4x

Combine like terms: 4x + -4x = 0
-10x = -80 + 0
-10x = -80

Divide each side by '-10'.
x = 8

Simplifying
x = 8

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