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2x(x-34)=1
We move all terms to the left:
2x(x-34)-(1)=0
We multiply parentheses
2x^2-68x-1=0
a = 2; b = -68; c = -1;
Δ = b2-4ac
Δ = -682-4·2·(-1)
Δ = 4632
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4632}=\sqrt{4*1158}=\sqrt{4}*\sqrt{1158}=2\sqrt{1158}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-68)-2\sqrt{1158}}{2*2}=\frac{68-2\sqrt{1158}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-68)+2\sqrt{1158}}{2*2}=\frac{68+2\sqrt{1158}}{4} $
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