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2x(x-4)=-6x-2
We move all terms to the left:
2x(x-4)-(-6x-2)=0
We multiply parentheses
2x^2-8x-(-6x-2)=0
We get rid of parentheses
2x^2-8x+6x+2=0
We add all the numbers together, and all the variables
2x^2-2x+2=0
a = 2; b = -2; c = +2;
Δ = b2-4ac
Δ = -22-4·2·2
Δ = -12
Delta is less than zero, so there is no solution for the equation
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