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2x(x-4)=180
We move all terms to the left:
2x(x-4)-(180)=0
We multiply parentheses
2x^2-8x-180=0
a = 2; b = -8; c = -180;
Δ = b2-4ac
Δ = -82-4·2·(-180)
Δ = 1504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1504}=\sqrt{16*94}=\sqrt{16}*\sqrt{94}=4\sqrt{94}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-4\sqrt{94}}{2*2}=\frac{8-4\sqrt{94}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+4\sqrt{94}}{2*2}=\frac{8+4\sqrt{94}}{4} $
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