2x(x-5)=(x+1)(2x-5)

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Solution for 2x(x-5)=(x+1)(2x-5) equation: 



2x(x-5)=(x+1)(2x-5)

We move all terms to the left:

2x(x-5)-((x+1)(2x-5))=0

We multiply parentheses

2x^2-10x-((x+1)(2x-5))=0

We multiply parentheses ..

2x^2-((+2x^2-5x+2x-5))-10x=0



We calculate terms in parentheses: -((+2x^2-5x+2x-5)), so:

(+2x^2-5x+2x-5)

We get rid of parentheses

2x^2-5x+2x-5

We add all the numbers together, and all the variables

2x^2-3x-5

Back to the equation:

-(2x^2-3x-5)



We add all the numbers together, and all the variables

2x^2-10x-(2x^2-3x-5)=0

We get rid of parentheses

2x^2-2x^2-10x+3x+5=0

We add all the numbers together, and all the variables

-7x+5=0

We move all terms containing x to the left, all other terms to the right

-7x=-5

x=-5/-7

x=5/7

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