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2x(x-8)=30
We move all terms to the left:
2x(x-8)-(30)=0
We multiply parentheses
2x^2-16x-30=0
a = 2; b = -16; c = -30;
Δ = b2-4ac
Δ = -162-4·2·(-30)
Δ = 496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{496}=\sqrt{16*31}=\sqrt{16}*\sqrt{31}=4\sqrt{31}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-4\sqrt{31}}{2*2}=\frac{16-4\sqrt{31}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+4\sqrt{31}}{2*2}=\frac{16+4\sqrt{31}}{4} $
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