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2x(x-x)-2x(x+x)=2x(2x-1)
We move all terms to the left:
2x(x-x)-2x(x+x)-(2x(2x-1))=0
We add all the numbers together, and all the variables
2x0-2x(+2x)-(2x(2x-1))=0
We add all the numbers together, and all the variables
2x-2x(+2x)-(2x(2x-1))=0
We multiply parentheses
-4x^2+2x-(2x(2x-1))=0
We calculate terms in parentheses: -(2x(2x-1)), so:We get rid of parentheses
2x(2x-1)
We multiply parentheses
4x^2-2x
Back to the equation:
-(4x^2-2x)
-4x^2-4x^2+2x+2x=0
We add all the numbers together, and all the variables
-8x^2+4x=0
a = -8; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·(-8)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*-8}=\frac{-8}{-16} =1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*-8}=\frac{0}{-16} =0 $
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