2x*(2*ln(x)+1)=0

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Solution for 2x*(2*ln(x)+1)=0 equation:


Simplifying
2x(2ln(x) + 1) = 0

Multiply ln * x
2x(2lnx + 1) = 0

Reorder the terms:
2x(1 + 2lnx) = 0
(1 * 2x + 2lnx * 2x) = 0

Reorder the terms:
(4lnx2 + 2x) = 0
(4lnx2 + 2x) = 0

Solving
4lnx2 + 2x = 0

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '-2x' to each side of the equation.
4lnx2 + 2x + -2x = 0 + -2x

Combine like terms: 2x + -2x = 0
4lnx2 + 0 = 0 + -2x
4lnx2 = 0 + -2x
Remove the zero:
4lnx2 = -2x

Divide each side by '4nx2'.
l = -0.5n-1x-1

Simplifying
l = -0.5n-1x-1

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