2x*(3+x)=6x-(x*x)

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Solution for 2x*(3+x)=6x-(x*x) equation: 



2x(3+x)=6x-(x*x)

We move all terms to the left:

2x(3+x)-(6x-(x*x))=0

We add all the numbers together, and all the variables

2x(x+3)-(6x-(+x*x))=0

We multiply parentheses

2x^2+6x-(6x-(+x*x))=0



We calculate terms in parentheses: -(6x-(+x*x)), so:

6x-(+x*x)

We get rid of parentheses

6x-x*x

Wy multiply elements

-1x^2+6x

Back to the equation:

-(-1x^2+6x)



We get rid of parentheses

2x^2+1x^2-6x+6x=0

We add all the numbers together, and all the variables

3x^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{6}=0$

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