2x*10x-4=20

Solution for 2x*10x-4=20 equation:

2x*10x-4=20

We move all terms to the left:

2x*10x-4-(20)=0

We add all the numbers together, and all the variables

2x*10x-24=0

Wy multiply elements

20x^2-24=0

a = 20; b = 0; c = -24;
Δ = b2-4ac
Δ = 02-4·20·(-24)
Δ = 1920
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1920}=\sqrt{64*30}=\sqrt{64}*\sqrt{30}=8\sqrt{30}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{30}}{2*20}=\frac{0-8\sqrt{30}}{40}
=-\frac{8\sqrt{30}}{40}
=-\frac{\sqrt{30}}{5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{30}}{2*20}=\frac{0+8\sqrt{30}}{40}
=\frac{8\sqrt{30}}{40}
=\frac{\sqrt{30}}{5}
$