2x*10x=95

Solution for 2x*10x=95 equation:

2x*10x=95

We move all terms to the left:

2x*10x-(95)=0

Wy multiply elements

20x^2-95=0

a = 20; b = 0; c = -95;
Δ = b2-4ac
Δ = 02-4·20·(-95)
Δ = 7600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7600}=\sqrt{400*19}=\sqrt{400}*\sqrt{19}=20\sqrt{19}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{19}}{2*20}=\frac{0-20\sqrt{19}}{40}
=-\frac{20\sqrt{19}}{40}
=-\frac{\sqrt{19}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{19}}{2*20}=\frac{0+20\sqrt{19}}{40}
=\frac{20\sqrt{19}}{40}
=\frac{\sqrt{19}}{2}
$