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2x*16x=6
We move all terms to the left:
2x*16x-(6)=0
Wy multiply elements
32x^2-6=0
a = 32; b = 0; c = -6;
Δ = b2-4ac
Δ = 02-4·32·(-6)
Δ = 768
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{768}=\sqrt{256*3}=\sqrt{256}*\sqrt{3}=16\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{3}}{2*32}=\frac{0-16\sqrt{3}}{64} =-\frac{16\sqrt{3}}{64} =-\frac{\sqrt{3}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{3}}{2*32}=\frac{0+16\sqrt{3}}{64} =\frac{16\sqrt{3}}{64} =\frac{\sqrt{3}}{4} $
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