2x*27x=544

Solution for 2x*27x=544 equation:

2x*27x=544

We move all terms to the left:

2x*27x-(544)=0

Wy multiply elements

54x^2-544=0

a = 54; b = 0; c = -544;
Δ = b2-4ac
Δ = 02-4·54·(-544)
Δ = 117504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{117504}=\sqrt{2304*51}=\sqrt{2304}*\sqrt{51}=48\sqrt{51}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48\sqrt{51}}{2*54}=\frac{0-48\sqrt{51}}{108}
=-\frac{48\sqrt{51}}{108}
=-\frac{4\sqrt{51}}{9}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48\sqrt{51}}{2*54}=\frac{0+48\sqrt{51}}{108}
=\frac{48\sqrt{51}}{108}
=\frac{4\sqrt{51}}{9}
$