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2x*2x+14x+70=110
We move all terms to the left:
2x*2x+14x+70-(110)=0
We add all the numbers together, and all the variables
14x+2x*2x-40=0
Wy multiply elements
4x^2+14x-40=0
a = 4; b = 14; c = -40;
Δ = b2-4ac
Δ = 142-4·4·(-40)
Δ = 836
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{836}=\sqrt{4*209}=\sqrt{4}*\sqrt{209}=2\sqrt{209}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{209}}{2*4}=\frac{-14-2\sqrt{209}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{209}}{2*4}=\frac{-14+2\sqrt{209}}{8} $
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