2x*2x+15=4x*4x-35

Solution for 2x*2x+15=4x*4x-35 equation:

2x*2x+15=4x*4x-35

We move all terms to the left:

2x*2x+15-(4x*4x-35)=0

Wy multiply elements

4x^2-(4x*4x-35)+15=0

We get rid of parentheses

4x^2-4x*4x+35+15=0

We add all the numbers together, and all the variables

4x^2-4x*4x+50=0

Wy multiply elements

4x^2-16x^2+50=0

We add all the numbers together, and all the variables

-12x^2+50=0

a = -12; b = 0; c = +50;
Δ = b2-4ac
Δ = 02-4·(-12)·50
Δ = 2400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2400}=\sqrt{400*6}=\sqrt{400}*\sqrt{6}=20\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{6}}{2*-12}=\frac{0-20\sqrt{6}}{-24}
=-\frac{20\sqrt{6}}{-24}
=-\frac{5\sqrt{6}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{6}}{2*-12}=\frac{0+20\sqrt{6}}{-24}
=\frac{20\sqrt{6}}{-24}
=\frac{5\sqrt{6}}{-6}
$