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2x*2x+3x-2=0
We add all the numbers together, and all the variables
3x+2x*2x-2=0
Wy multiply elements
4x^2+3x-2=0
a = 4; b = 3; c = -2;
Δ = b2-4ac
Δ = 32-4·4·(-2)
Δ = 41
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{41}}{2*4}=\frac{-3-\sqrt{41}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{41}}{2*4}=\frac{-3+\sqrt{41}}{8} $
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