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2x*2x-2x=12
We move all terms to the left:
2x*2x-2x-(12)=0
We add all the numbers together, and all the variables
-2x+2x*2x-12=0
Wy multiply elements
4x^2-2x-12=0
a = 4; b = -2; c = -12;
Δ = b2-4ac
Δ = -22-4·4·(-12)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-14}{2*4}=\frac{-12}{8} =-1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+14}{2*4}=\frac{16}{8} =2 $
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