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2x*3+25=16(x/4)
We move all terms to the left:
2x*3+25-(16(x/4))=0
We add all the numbers together, and all the variables
2x*3-(16(+x/4))+25=0
Wy multiply elements
6x-(16(+x/4))+25=0
We multiply all the terms by the denominator
6x*4))-(16(+x+25*4))=0
We add all the numbers together, and all the variables
6x*4))-(16(x+100))=0
We add all the numbers together, and all the variables
6x*4))-(16(x=0
Wy multiply elements
24x^2=0
a = 24; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·24·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{48}=0$
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