2x*3x=100

Solution for 2x*3x=100 equation:

2x*3x=100

We move all terms to the left:

2x*3x-(100)=0

Wy multiply elements

6x^2-100=0

a = 6; b = 0; c = -100;
Δ = b2-4ac
Δ = 02-4·6·(-100)
Δ = 2400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2400}=\sqrt{400*6}=\sqrt{400}*\sqrt{6}=20\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{6}}{2*6}=\frac{0-20\sqrt{6}}{12}
=-\frac{20\sqrt{6}}{12}
=-\frac{5\sqrt{6}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{6}}{2*6}=\frac{0+20\sqrt{6}}{12}
=\frac{20\sqrt{6}}{12}
=\frac{5\sqrt{6}}{3}
$