2x*3x=1440

Solution for 2x*3x=1440 equation:

2x*3x=1440

We move all terms to the left:

2x*3x-(1440)=0

Wy multiply elements

6x^2-1440=0

a = 6; b = 0; c = -1440;
Δ = b2-4ac
Δ = 02-4·6·(-1440)
Δ = 34560
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{34560}=\sqrt{2304*15}=\sqrt{2304}*\sqrt{15}=48\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48\sqrt{15}}{2*6}=\frac{0-48\sqrt{15}}{12}
=-\frac{48\sqrt{15}}{12}
=-4\sqrt{15}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48\sqrt{15}}{2*6}=\frac{0+48\sqrt{15}}{12}
=\frac{48\sqrt{15}}{12}
=4\sqrt{15}
$