2x*3x=1800

Solution for 2x*3x=1800 equation:

2x*3x=1800

We move all terms to the left:

2x*3x-(1800)=0

Wy multiply elements

6x^2-1800=0

a = 6; b = 0; c = -1800;
Δ = b2-4ac
Δ = 02-4·6·(-1800)
Δ = 43200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{43200}=\sqrt{14400*3}=\sqrt{14400}*\sqrt{3}=120\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120\sqrt{3}}{2*6}=\frac{0-120\sqrt{3}}{12}
=-\frac{120\sqrt{3}}{12}
=-10\sqrt{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120\sqrt{3}}{2*6}=\frac{0+120\sqrt{3}}{12}
=\frac{120\sqrt{3}}{12}
=10\sqrt{3}
$