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2x*3x=200
We move all terms to the left:
2x*3x-(200)=0
Wy multiply elements
6x^2-200=0
a = 6; b = 0; c = -200;
Δ = b2-4ac
Δ = 02-4·6·(-200)
Δ = 4800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4800}=\sqrt{1600*3}=\sqrt{1600}*\sqrt{3}=40\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40\sqrt{3}}{2*6}=\frac{0-40\sqrt{3}}{12} =-\frac{40\sqrt{3}}{12} =-\frac{10\sqrt{3}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40\sqrt{3}}{2*6}=\frac{0+40\sqrt{3}}{12} =\frac{40\sqrt{3}}{12} =\frac{10\sqrt{3}}{3} $
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