2x*3x=80

Solution for 2x*3x=80 equation:

2x*3x=80

We move all terms to the left:

2x*3x-(80)=0

Wy multiply elements

6x^2-80=0

a = 6; b = 0; c = -80;
Δ = b2-4ac
Δ = 02-4·6·(-80)
Δ = 1920
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1920}=\sqrt{64*30}=\sqrt{64}*\sqrt{30}=8\sqrt{30}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{30}}{2*6}=\frac{0-8\sqrt{30}}{12}
=-\frac{8\sqrt{30}}{12}
=-\frac{2\sqrt{30}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{30}}{2*6}=\frac{0+8\sqrt{30}}{12}
=\frac{8\sqrt{30}}{12}
=\frac{2\sqrt{30}}{3}
$