2x*3x=94

Solution for 2x*3x=94 equation:

2x*3x=94

We move all terms to the left:

2x*3x-(94)=0

Wy multiply elements

6x^2-94=0

a = 6; b = 0; c = -94;
Δ = b2-4ac
Δ = 02-4·6·(-94)
Δ = 2256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2256}=\sqrt{16*141}=\sqrt{16}*\sqrt{141}=4\sqrt{141}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{141}}{2*6}=\frac{0-4\sqrt{141}}{12}
=-\frac{4\sqrt{141}}{12}
=-\frac{\sqrt{141}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{141}}{2*6}=\frac{0+4\sqrt{141}}{12}
=\frac{4\sqrt{141}}{12}
=\frac{\sqrt{141}}{3}
$