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2x*4.25x=65
We move all terms to the left:
2x*4.25x-(65)=0
Wy multiply elements
8x^2-65=0
a = 8; b = 0; c = -65;
Δ = b2-4ac
Δ = 02-4·8·(-65)
Δ = 2080
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2080}=\sqrt{16*130}=\sqrt{16}*\sqrt{130}=4\sqrt{130}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{130}}{2*8}=\frac{0-4\sqrt{130}}{16} =-\frac{4\sqrt{130}}{16} =-\frac{\sqrt{130}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{130}}{2*8}=\frac{0+4\sqrt{130}}{16} =\frac{4\sqrt{130}}{16} =\frac{\sqrt{130}}{4} $
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