2x*4x=2000

Solution for 2x*4x=2000 equation:

2x*4x=2000

We move all terms to the left:

2x*4x-(2000)=0

Wy multiply elements

8x^2-2000=0

a = 8; b = 0; c = -2000;
Δ = b2-4ac
Δ = 02-4·8·(-2000)
Δ = 64000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{64000}=\sqrt{6400*10}=\sqrt{6400}*\sqrt{10}=80\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-80\sqrt{10}}{2*8}=\frac{0-80\sqrt{10}}{16}
=-\frac{80\sqrt{10}}{16}
=-5\sqrt{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+80\sqrt{10}}{2*8}=\frac{0+80\sqrt{10}}{16}
=\frac{80\sqrt{10}}{16}
=5\sqrt{10}
$