2x*8x-4=70

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Solution for 2x*8x-4=70 equation:



2x*8x-4=70
We move all terms to the left:
2x*8x-4-(70)=0
We add all the numbers together, and all the variables
2x*8x-74=0
Wy multiply elements
16x^2-74=0
a = 16; b = 0; c = -74;
Δ = b2-4ac
Δ = 02-4·16·(-74)
Δ = 4736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{4736}=\sqrt{64*74}=\sqrt{64}*\sqrt{74}=8\sqrt{74}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{74}}{2*16}=\frac{0-8\sqrt{74}}{32} =-\frac{8\sqrt{74}}{32} =-\frac{\sqrt{74}}{4} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{74}}{2*16}=\frac{0+8\sqrt{74}}{32} =\frac{8\sqrt{74}}{32} =\frac{\sqrt{74}}{4} $

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