2x*9x=45

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Solution for 2x*9x=45 equation:



2x*9x=45
We move all terms to the left:
2x*9x-(45)=0
Wy multiply elements
18x^2-45=0
a = 18; b = 0; c = -45;
Δ = b2-4ac
Δ = 02-4·18·(-45)
Δ = 3240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{3240}=\sqrt{324*10}=\sqrt{324}*\sqrt{10}=18\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18\sqrt{10}}{2*18}=\frac{0-18\sqrt{10}}{36} =-\frac{18\sqrt{10}}{36} =-\frac{\sqrt{10}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18\sqrt{10}}{2*18}=\frac{0+18\sqrt{10}}{36} =\frac{18\sqrt{10}}{36} =\frac{\sqrt{10}}{2} $

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