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2x*9x=91
We move all terms to the left:
2x*9x-(91)=0
Wy multiply elements
18x^2-91=0
a = 18; b = 0; c = -91;
Δ = b2-4ac
Δ = 02-4·18·(-91)
Δ = 6552
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6552}=\sqrt{36*182}=\sqrt{36}*\sqrt{182}=6\sqrt{182}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{182}}{2*18}=\frac{0-6\sqrt{182}}{36} =-\frac{6\sqrt{182}}{36} =-\frac{\sqrt{182}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{182}}{2*18}=\frac{0+6\sqrt{182}}{36} =\frac{6\sqrt{182}}{36} =\frac{\sqrt{182}}{6} $
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