2x*x+23x+56=56

Solution for 2x*x+23x+56=56 equation:

2x*x+23x+56=56

We move all terms to the left:

2x*x+23x+56-(56)=0

We add all the numbers together, and all the variables

23x+2x*x=0

Wy multiply elements

2x^2+23x=0

a = 2; b = 23; c = 0;
Δ = b2-4ac
Δ = 232-4·2·0
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-23}{2*2}=\frac{-46}{4}
=-11+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+23}{2*2}=\frac{0}{4}
=0
$