2x*x+4x-1=7x*x-7x+1

Solution for 2x*x+4x-1=7x*x-7x+1 equation:

2x*x+4x-1=7x*x-7x+1

We move all terms to the left:

2x*x+4x-1-(7x*x-7x+1)=0

We add all the numbers together, and all the variables

2x*x+4x-(-7x+7x*x+1)-1=0

We add all the numbers together, and all the variables

4x+2x*x-(-7x+7x*x+1)-1=0

Wy multiply elements

2x^2+4x-(-7x+7x*x+1)-1=0

We get rid of parentheses

2x^2+4x+7x-7x*x-1-1=0

We add all the numbers together, and all the variables

2x^2+11x-7x*x-2=0

Wy multiply elements

2x^2-7x^2+11x-2=0

We add all the numbers together, and all the variables

-5x^2+11x-2=0

a = -5; b = 11; c = -2;
Δ = b2-4ac
Δ = 112-4·(-5)·(-2)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-9}{2*-5}=\frac{-20}{-10}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+9}{2*-5}=\frac{-2}{-10}
=1/5
$