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2x*x=145
We move all terms to the left:
2x*x-(145)=0
Wy multiply elements
2x^2-145=0
a = 2; b = 0; c = -145;
Δ = b2-4ac
Δ = 02-4·2·(-145)
Δ = 1160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1160}=\sqrt{4*290}=\sqrt{4}*\sqrt{290}=2\sqrt{290}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{290}}{2*2}=\frac{0-2\sqrt{290}}{4} =-\frac{2\sqrt{290}}{4} =-\frac{\sqrt{290}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{290}}{2*2}=\frac{0+2\sqrt{290}}{4} =\frac{2\sqrt{290}}{4} =\frac{\sqrt{290}}{2} $
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