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2x*x=3000
We move all terms to the left:
2x*x-(3000)=0
Wy multiply elements
2x^2-3000=0
a = 2; b = 0; c = -3000;
Δ = b2-4ac
Δ = 02-4·2·(-3000)
Δ = 24000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{24000}=\sqrt{1600*15}=\sqrt{1600}*\sqrt{15}=40\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40\sqrt{15}}{2*2}=\frac{0-40\sqrt{15}}{4} =-\frac{40\sqrt{15}}{4} =-10\sqrt{15} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40\sqrt{15}}{2*2}=\frac{0+40\sqrt{15}}{4} =\frac{40\sqrt{15}}{4} =10\sqrt{15} $
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