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2x+((12-4x)/2)=6
We move all terms to the left:
2x+((12-4x)/2)-(6)=0
We add all the numbers together, and all the variables
2x+((-4x+12)/2)-6=0
We multiply all the terms by the denominator
2x*2)+((-4x+12)-6*2)=0
We add all the numbers together, and all the variables
2x*2)+((-4x+12)=0
Wy multiply elements
4x^2=0
a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{8}=0$
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