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2x+((6-x)/3)=-3
We move all terms to the left:
2x+((6-x)/3)-(-3)=0
We add all the numbers together, and all the variables
2x+((-1x+6)/3)-(-3)=0
We add all the numbers together, and all the variables
2x+((-1x+6)/3)+3=0
We multiply all the terms by the denominator
2x*3)+((-1x+6)+3*3)=0
We add all the numbers together, and all the variables
2x*3)+((-1x+6)=0
Wy multiply elements
6x^2=0
a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{12}=0$
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