2x+(-2/7x)=70

Solution for 2x+(-2/7x)=70 equation:

2x+(-2/7x)=70

We move all terms to the left:

2x+(-2/7x)-(70)=0


Domain of the equation: 7x)!=0

x!=0/1

x!=0

x∈R


We get rid of parentheses

2x-2/7x-70=0

We multiply all the terms by the denominator


2x*7x-70*7x-2=0

Wy multiply elements

14x^2-490x-2=0

a = 14; b = -490; c = -2;
Δ = b2-4ac
Δ = -4902-4·14·(-2)
Δ = 240212
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{240212}=\sqrt{4*60053}=\sqrt{4}*\sqrt{60053}=2\sqrt{60053}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-490)-2\sqrt{60053}}{2*14}=\frac{490-2\sqrt{60053}}{28}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-490)+2\sqrt{60053}}{2*14}=\frac{490+2\sqrt{60053}}{28}
$