2x+(-6-x)=2-3(x+5)

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Solution for 2x+(-6-x)=2-3(x+5) equation: 



2x+(-6-x)=2-3(x+5)

We move all terms to the left:

2x+(-6-x)-(2-3(x+5))=0

We add all the numbers together, and all the variables

2x+(-1x-6)-(2-3(x+5))=0

We get rid of parentheses

2x-1x-(2-3(x+5))-6=0



We calculate terms in parentheses: -(2-3(x+5)), so:

2-3(x+5)

determiningTheFunctionDomain
-3(x+5)+2

We multiply parentheses

-3x-15+2

We add all the numbers together, and all the variables

-3x-13

Back to the equation:

-(-3x-13)



We add all the numbers together, and all the variables

x-(-3x-13)-6=0

We get rid of parentheses

x+3x+13-6=0

We add all the numbers together, and all the variables

4x+7=0

We move all terms containing x to the left, all other terms to the right

4x=-7

x=-7/4

x=-1+3/4

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