2x+(17422/x)=395

Solution for 2x+(17422/x)=395 equation:

2x+(17422/x)=395

We move all terms to the left:

2x+(17422/x)-(395)=0


Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2x+(+17422/x)-395=0

We get rid of parentheses

2x+17422/x-395=0

We multiply all the terms by the denominator


2x*x-395*x+17422=0

We add all the numbers together, and all the variables

-395x+2x*x+17422=0

Wy multiply elements

2x^2-395x+17422=0

a = 2; b = -395; c = +17422;
Δ = b2-4ac
Δ = -3952-4·2·17422
Δ = 16649
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-395)-\sqrt{16649}}{2*2}=\frac{395-\sqrt{16649}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-395)+\sqrt{16649}}{2*2}=\frac{395+\sqrt{16649}}{4}
$