2x+(2x/3)=35

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Solution for 2x+(2x/3)=35 equation:



2x+(2x/3)=35
We move all terms to the left:
2x+(2x/3)-(35)=0
We add all the numbers together, and all the variables
2x+(+2x/3)-35=0
We get rid of parentheses
2x+2x/3-35=0
We multiply all the terms by the denominator
2x*3+2x-35*3=0
We add all the numbers together, and all the variables
2x+2x*3-105=0
Wy multiply elements
2x+6x-105=0
We add all the numbers together, and all the variables
8x-105=0
We move all terms containing x to the left, all other terms to the right
8x=105
x=105/8
x=13+1/8

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