2x+(3-x)+8=2(x-3)

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Solution for 2x+(3-x)+8=2(x-3) equation:



2x+(3-x)+8=2(x-3)
We move all terms to the left:
2x+(3-x)+8-(2(x-3))=0
We add all the numbers together, and all the variables
2x+(-1x+3)-(2(x-3))+8=0
We get rid of parentheses
2x-1x-(2(x-3))+3+8=0
We calculate terms in parentheses: -(2(x-3)), so:
2(x-3)
We multiply parentheses
2x-6
Back to the equation:
-(2x-6)
We add all the numbers together, and all the variables
x-(2x-6)+11=0
We get rid of parentheses
x-2x+6+11=0
We add all the numbers together, and all the variables
-1x+17=0
We move all terms containing x to the left, all other terms to the right
-x=-17
x=-17/-1
x=+17

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