2x+(3-x)+8=2(x-3)

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Solution for 2x+(3-x)+8=2(x-3) equation: 



2x+(3-x)+8=2(x-3)

We move all terms to the left:

2x+(3-x)+8-(2(x-3))=0

We add all the numbers together, and all the variables

2x+(-1x+3)-(2(x-3))+8=0

We get rid of parentheses

2x-1x-(2(x-3))+3+8=0



We calculate terms in parentheses: -(2(x-3)), so:

2(x-3)

We multiply parentheses

2x-6

Back to the equation:

-(2x-6)



We add all the numbers together, and all the variables

x-(2x-6)+11=0

We get rid of parentheses

x-2x+6+11=0

We add all the numbers together, and all the variables

-1x+17=0

We move all terms containing x to the left, all other terms to the right

-x=-17

x=-17/-1

x=+17

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