2x+(32-4x)=23

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Solution for 2x+(32-4x)=23 equation: 



2x+(32-4x)=23

We move all terms to the left:

2x+(32-4x)-(23)=0

We add all the numbers together, and all the variables

2x+(-4x+32)-23=0

We get rid of parentheses

2x-4x+32-23=0

We add all the numbers together, and all the variables

-2x+9=0

We move all terms containing x to the left, all other terms to the right

-2x=-9

x=-9/-2

x=4+1/2

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