2x+(3X-(4+x))=20

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Solution for 2x+(3X-(4+x))=20 equation: 


Simplifying
2x + (3X + -1(4 + x)) = 20
2x + (3X + (4 * -1 + x * -1)) = 20
2x + (3X + (-4 + -1x)) = 20

Reorder the terms:
2x + (-4 + 3X + -1x) = 20

Remove parenthesis around (-4 + 3X + -1x)
2x + -4 + 3X + -1x = 20

Reorder the terms:
-4 + 3X + 2x + -1x = 20

Combine like terms: 2x + -1x = 1x
-4 + 3X + 1x = 20

Solving
-4 + 3X + 1x = 20

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 3X + 4 + 1x = 20 + 4

Reorder the terms:
-4 + 4 + 3X + 1x = 20 + 4

Combine like terms: -4 + 4 = 0
0 + 3X + 1x = 20 + 4
3X + 1x = 20 + 4

Combine like terms: 20 + 4 = 24
3X + 1x = 24

Add '-1x' to each side of the equation.
3X + 1x + -1x = 24 + -1x

Combine like terms: 1x + -1x = 0
3X + 0 = 24 + -1x
3X = 24 + -1x

Divide each side by '3'.
X = 8 + -0.3333333333x

Simplifying
X = 8 + -0.3333333333x

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