2x+(3x+1)+2(x+3)=35

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Solution for 2x+(3x+1)+2(x+3)=35 equation: 



2x+(3x+1)+2(x+3)=35

We move all terms to the left:

2x+(3x+1)+2(x+3)-(35)=0

We multiply parentheses

2x+(3x+1)+2x+6-35=0

We get rid of parentheses

2x+3x+2x+1+6-35=0

We add all the numbers together, and all the variables

7x-28=0

We move all terms containing x to the left, all other terms to the right

7x=28

x=28/7

x=4

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