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2x+(3x+8)=(3x-4)
We move all terms to the left:
2x+(3x+8)-((3x-4))=0
We get rid of parentheses
2x+3x-((3x-4))+8=0
We calculate terms in parentheses: -((3x-4)), so:We add all the numbers together, and all the variables
(3x-4)
We get rid of parentheses
3x-4
Back to the equation:
-(3x-4)
5x-(3x-4)+8=0
We get rid of parentheses
5x-3x+4+8=0
We add all the numbers together, and all the variables
2x+12=0
We move all terms containing x to the left, all other terms to the right
2x=-12
x=-12/2
x=-6
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