2x+(3x-10)=140

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Solution for 2x+(3x-10)=140 equation: 



2x+(3x-10)=140

We move all terms to the left:

2x+(3x-10)-(140)=0

We get rid of parentheses

2x+3x-10-140=0

We add all the numbers together, and all the variables

5x-150=0

We move all terms containing x to the left, all other terms to the right

5x=150

x=150/5

x=30

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