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2x+(3x-4)=4(2x+3)
We move all terms to the left:
2x+(3x-4)-(4(2x+3))=0
We get rid of parentheses
2x+3x-(4(2x+3))-4=0
We calculate terms in parentheses: -(4(2x+3)), so:We add all the numbers together, and all the variables
4(2x+3)
We multiply parentheses
8x+12
Back to the equation:
-(8x+12)
5x-(8x+12)-4=0
We get rid of parentheses
5x-8x-12-4=0
We add all the numbers together, and all the variables
-3x-16=0
We move all terms containing x to the left, all other terms to the right
-3x=16
x=16/-3
x=-5+1/3
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