2x+(3x-5)+(19-x)=(3x-5)+(19-5)+2x

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Solution for 2x+(3x-5)+(19-x)=(3x-5)+(19-5)+2x equation: 



2x+(3x-5)+(19-x)=(3x-5)+(19-5)+2x

We move all terms to the left:

2x+(3x-5)+(19-x)-((3x-5)+(19-5)+2x)=0

We add all the numbers together, and all the variables

2x+(3x-5)+(-1x+19)-((3x-5)+14+2x)=0

We get rid of parentheses

2x+3x-1x-((3x-5)+14+2x)-5+19=0



We calculate terms in parentheses: -((3x-5)+14+2x), so:

(3x-5)+14+2x

determiningTheFunctionDomain
(3x-5)+2x+14

We add all the numbers together, and all the variables

2x+(3x-5)+14

We get rid of parentheses

2x+3x-5+14

We add all the numbers together, and all the variables

5x+9

Back to the equation:

-(5x+9)



We add all the numbers together, and all the variables

4x-(5x+9)+14=0

We get rid of parentheses

4x-5x-9+14=0

We add all the numbers together, and all the variables

-1x+5=0

We move all terms containing x to the left, all other terms to the right

-x=-5

x=-5/-1

x=+5

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