2x+(3x-5)=6x+(7x-2)

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Solution for 2x+(3x-5)=6x+(7x-2) equation: 



2x+(3x-5)=6x+(7x-2)

We move all terms to the left:

2x+(3x-5)-(6x+(7x-2))=0

We get rid of parentheses

2x+3x-(6x+(7x-2))-5=0



We calculate terms in parentheses: -(6x+(7x-2)), so:

6x+(7x-2)

We get rid of parentheses

6x+7x-2

We add all the numbers together, and all the variables

13x-2

Back to the equation:

-(13x-2)



We add all the numbers together, and all the variables

5x-(13x-2)-5=0

We get rid of parentheses

5x-13x+2-5=0

We add all the numbers together, and all the variables

-8x-3=0

We move all terms containing x to the left, all other terms to the right

-8x=3

x=3/-8

x=-3/8

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